# Line slope calculator 3x-5y=-9

**Straight line given by points A[2; 3] and B[7; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+1.8

**Canonical form of the line equation:**3x-5y+9 = 0

**Parametric form of the line equation:**

x = 5t+2

y = 3t+3 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -3

**Y intercept:**y

_{0}= q = 1.8

**Distance line from the origin:**d

_{0}= 1.5435

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[4.5; 4.5]

**Perpendicular Bisector equation:**5x+3y-36 = 0

**Vector OA = (2; 3) ; |OA| = 3.6056**

**Vector OB = (7; 6) ; |OB| = 9.2195**

**Scalar product OA .OB = 32**

**Angle ∠ AOB = 15°42'31″ = 0.2742 rad**